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Enigme Avec Reponse Pdf ^HOT^

Enigme Avec Reponse Pdf: The Ultimate Collection of Brain Teasers

Do you love puzzles and riddles? Do you enjoy challenging your mind and having fun at the same time? If so, you will love Enigme Avec Reponse Pdf, a collection of 50 enigmes and casse têtes that will test your logic, creativity and imagination.

Enigme Avec Reponse Pdf

Enigme Avec Reponse Pdf is a French term that means "puzzle with answer pdf". It is a type of puzzle that consists of a question, a clue or a situation that requires you to find the solution using your reasoning skills. Some enigmes are easy, some are hard, and some are downright tricky. But they are all entertaining and stimulating.

In this article, we will show you some examples of Enigme Avec Reponse Pdf puzzles and their solutions. You can download the full pdf file from the link below and print it out or read it on your device. You can also share it with your friends and family and challenge them to solve the puzzles with you.

Are you ready to embark on an adventure of enigmes and casse têtes? Let's get started!

Example 4: The cigarette maker

A homeless man likes to smoke but cannot afford to buy cigarettes. He has found a trick. He collects cigarette butts and with the remaining tobacco he rolls cigarettes. With 3 cigarette butts he can make one cigarette. How many cigarettes can he smoke with 10 cigarette butts?

Solution: 4 cigarettes. He can make 3 cigarettes with 9 cigarette butts, and then he will have 3 more cigarette butts left. With these 3 cigarette butts, he can make one more cigarette.

Example 5: The party

A man in an apartment cannot sleep because of his neighbor upstairs who is having a small party with some friends. To pass the time, he counts the clinking of glasses when they toast. He counts 28 clinks. How many people are at the party?

Solution: 8 people. If there are n people at the party, then each person will toast with n-1 other people, and there will be n(n-1)/2 clinks in total. So we have to solve the equation n(n-1)/2 = 28, which gives n = 8.

Example 6: The cheese

A man walks in the mountains and meets two shepherds who are about to eat. He asks them if he can share their meal. The shepherds agree. The first shepherd has 7 cheeses, and the second one has 5. They all sit down and eat four cheeses each. To compensate them, the walker gives them 12 francs. The first one takes 7 francs and the second one takes 5 francs. Is the sharing fair?

Solution: No, it is not fair. The first shepherd had 7 cheeses and ate 4, so he gave 3 cheeses to the walker. The second shepherd had 5 cheeses and ate 4, so he gave only one cheese to the walker. Therefore, the first shepherd should receive more money than the second one. A fair sharing would be to give 9 francs to the first shepherd and 3 francs to the second one.

Example 7: The camels

A man from the desert has just died. He had 17 camels. He wishes, according to his will, to leave half of his camels to his first son, a third to his second son, and a ninth to his third son. Seventeen is not divisible by 2, nor by 3, nor by 9. How to share the camels?

Solution: A wise man comes and adds his own camel to the 17 camels. Now there are 18 camels. He gives half of them (9) to the first son, a third of them (6) to the second son, and a ninth of them (2) to the third son. In total, he has given 9 + 6 + 2 = 17 camels. He takes back his own camel and leaves.

Example 8: The snail

A snail has fallen into a well of twelve meters. He climbs the wall to get back to the surface. During the day, he climbs three meters, but at night, when he sleeps, he slides down two meters. How many days will it take the snail to get out?

Solution: 10 days. On the first day, he climbs three meters and slides down two meters at night, so he is one meter above the bottom. On the second day, he climbs three more meters and slides down two meters at night, so he is two meters above the bottom. And so on until the ninth day, when he is eight meters above the bottom. On the tenth day, he climbs three more meters and reaches the surface before sliding down at night.

Example 9: The bikers and the fly

Two villages A and B are separated by 80 km. Two bikers leave at the same time from each village, one at twenty km/h, the other at sixty km/h. A very sporty fly flies at 100 km/h. It leaves at the same time as the first biker from village A and alternately reaches the two bikers until they cross each other. So when it reaches one biker, it turns around and flies to the other biker, and so on. How far will the fly have flown when they cross?

Solution: 50 km. The two bikers will cross each other after one hour of travel (the first one will have traveled 20 km and the second one will have traveled 60 km). The fly will have flown for one hour at 100 km/h, so it will have covered 100 km.

Example 10: The pizza

You have a pizza and place it in front of you. How many pieces can you cut it into with only six cuts of a knife?

Solution: 22 pieces. You can cut the pizza into four equal parts with two cuts, then stack them and cut them again with two more cuts. You will have 16 pieces. Then you can stack these pieces and cut them diagonally with the last two cuts. You will have 22 pieces.

Example 11: The bridge

Four people want to cross a bridge at night. They only have one flashlight and the bridge can only hold two people at a time. The flashlight must be used to cross the bridge and cannot be thrown or left on the bridge. The four people take different times to cross the bridge: 1 minute, 2 minutes, 5 minutes and 10 minutes. What is the shortest time they can all cross the bridge?

Solution: 17 minutes. One possible way is: The 1-minute person and the 2-minute person cross together (2 minutes). The 1-minute person goes back with the flashlight (1 minute). The 5-minute person and the 10-minute person cross together (10 minutes). The 2-minute person goes back with the flashlight (2 minutes). The 1-minute person and the 2-minute person cross together again (2 minutes).

Example 12: The coins

You have twelve coins that look identical, but one of them is either heavier or lighter than the others. You also have a balance scale that you can use to compare the weight of two sets of coins. How can you find out which coin is different and whether it is heavier or lighter in only three weighings?

Solution: One possible way is: Divide the coins into three groups of four coins each. Weigh two groups against each other. If they balance, then the different coin is in the third group. If they don't balance, then the different coin is in the group that is heavier or lighter. In either case, take the group that contains the different coin and divide it into two groups of two coins each. Weigh them against each other. If they balance, then the different coin is one of the remaining two coins. If they don't balance, then the different coin is one of the two coins on the scale. In either case, take the two coins that could be different and weigh one against another. If they balance, then you have found the different coin (the one that was not weighed). If they don't balance, then you have also found the different coin (the one that is heavier or lighter).

Example 13: The inheritance

A father has three sons and a large fortune. He decides to leave his entire fortune to one of his sons, but he does not know which one. He gives each son a coin and tells them to buy something that can fill their living room. The first son buys straw, but there is not enough to fill the room. The second son buys feathers, but there is still some empty space. The third son buys two things that fill the room completely. What are they?

Solution: A candle and a match. When he lights the candle, the light fills the room.

Example 14: The prisoners

Three prisoners are in a cell. They have no way of communicating with each other. The jailer tells them that he will free one of them if he can guess the color of his hat. He also tells them that there are three hats: two black and one white. He puts a hat on each prisoner's head and leaves them alone. The first prisoner looks at the other two and says nothing. The second prisoner looks at the third one and says nothing. The third prisoner, who is blind, says the color of his hat correctly. How did he do it?

Solution: Black. The third prisoner reasoned that if the first prisoner saw two white hats, he would have said white immediately, since he knew there was only one white hat. But since he said nothing, it meant that he saw at least one black hat. Then the third prisoner thought that if the second prisoner saw a white hat on the third prisoner's head, he would have said black, since he knew that the first prisoner saw at least one black hat and did not say anything. But since he also said nothing, it meant that he saw a black hat on the third prisoner's head. Therefore, the third prisoner concluded that his hat was black.

Example 15: The riddle

This thing all things devours: Birds, beasts, trees, flowers; Gnaws iron, bites steel; Grinds hard stones to meal; Slays king, ruins town, And beats high mountain down.

Solution: Time.

Example 16: The socks